The first term of an arithmetic sequence is 6 and the common difference is 4. How many terms
must be added together until the sum of the terms is equal to 510?
Answers
Step-by-step explanation:
a=6
d=4
n= ?
Sn= 510
wkt
Sn = n/2[2a+ (n-1)d
510= n/2[12+ (n-1)4
510×2 = n( 12+4n-4)
1020 = 4n² +8n
4n² + 8n -1020= 0
by solving above equation
we get x = 15 and -17
since n can't be negative
so 15 terms should be added to get the sum of 510
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Answer:
Step-by-step explanation:
Definition of arithmetic sequence:
An arithmetic sequence is one in which each phrase grows by adding or removing a certain constant, k. In a geometric sequence, each term rises by dividing by or multiplying by a certain constant k. For instance, a1 = 25 and a(n) = a(n-1) + 5.
Given:
arithmetic sequence = 6
common difference = 4
Sn = 510
Find:
How many terms must be added together until the sum of the terms is equal to 510
Solution:
Sn = n/2[2a+ (n-1)d
510= n/2[12+ (n-1)4
510×2 = n( 12+4n-4)
1020 = 4n² +8n
4n² + 8n -1020= 0
by solving above equation
we get x = 15 and -17
since n can't be negative
Hence 15 terms should be added to get the sum of 510.
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