the first term of ap is -5 and last term is 4 .if sum is 120, find n and d
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the value of n= - 240 hope it is helpful 2 u
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Correct question :
the first term of ap is -5 and last term is 45 .if sum is 120, find n and d
Solution :
Let us consider an A.P. whose first term and common difference are a and d respectively.
Here, a = -5, a_n = 45, S_n = 120
Now, S_n = n/2[2a+(n - 1)d] = n/2[a+a+(n-1)d]
s_n = n/2 [a + a_n][a_n = last term]
120= n/2 (-5 + 45)
120 = n/2 x 40
n = 120x2/40 = 6
n = 6
Hence, the number of terms = 6
Now, a_n = a + (n-1)d
45 = -5 + (6-1)d
45 = 5 - 5d
5d = 50
d = 50/5
d = 10
=> Hence, the common difference and the number of terms in A.P. are 10 and 6 respectively.
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