The first term of AP is -5 and last term is 45 .If sum f ap is 120.then find no. Of termand d
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Answer:
number of term is 6 and difference is 10
Step-by-step explanation:
120=n/2(a+l)
120=n/2(-5+45)
120=n/2(40)
120=20n
n=120/20
n=6
120=6/2(2×-5+(6-1)d)
120=3(-10+5d)
-10+5d=40
5d=40+10
5d=50
d=10
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