the first term of AP is 5 the commn difference is 3 and the last is 80 find the number of terms
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24 terms
Explanation:
suppose there are n terms.nth term is 80
eqn.for nth term is a+(n-1)d
so 5+(n-1)3=80
3n=72,n=24
Answered by
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So, with the given information, we can say that
a = 5
d = 3
a n = 80
Now, let’s use the formula for a n (supposed to be a subscript n)
a n = a + (n-1)d
80 = 5 + (n-1)3
80 - 5 = (n-1)3
75 = (n-1)3
75/3 = (n-1)
25 = n-1
n = 25 + 1 = 26.
Therefore, no. of terms in given AP = 26.
a = 5
d = 3
a n = 80
Now, let’s use the formula for a n (supposed to be a subscript n)
a n = a + (n-1)d
80 = 5 + (n-1)3
80 - 5 = (n-1)3
75 = (n-1)3
75/3 = (n-1)
25 = n-1
n = 25 + 1 = 26.
Therefore, no. of terms in given AP = 26.
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