The first term of Ap is p and its common difference is q .find its 10th and 100th term
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The 10th term of an AP is (p + 9q).
The first term of an A.P. is p and its common difference is q.
First term(a) = p, d = q
By using the formula , nth term of an AP , an = a + (n - 1)d
a10 = p + (10 - 1)q
a10 = (p + 9q)
Hence , the 10th term of an AP is (p + 9q).
Similiarly, a100=p+(100-1)q
Hence , the 100th term of an AP is (p + 99q).
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Answer: a10= p+9q and a100= p+99q
Step-by-step explanation:
i) a= p
b= q
nth term= 10
a nth term= a+(n-1)d
a 10th term= p+(10-1)q
= p+9q
ii) a= p
b= q
nth term= 100
a nth term= a+(n-1)d
a 10th term= p+(100-1)q
= p+99q
10th term= p+9q
100th term= p+99q
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