the first term of arithmetic sequence is 10. thr sum offirst 5 terms is 250 find the sequence
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Answer:
10, 30, 50...
Step-by-step explanation:
Given, a = 10. Let the common difference be d.
Sum of n terms: (n/2) [2a + (n - 1)d]
Sum of 5 terms = (5/2) [2(10) + (5 - 1)d]
=> 250 = (5/2) [20 + 4d]
=> 100 = 20 + 4d
=> 80 = 4d
=> 20 = d
Therefore, the sequence is:
a = 10
a + d = 10 + 20 = 30
a + 2d = 10 + 2(20) = 50
Step-by-step explanation:
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