The first term of two A.P.s are equal and the ratios of their common differences is 1:2 . if the 7th term of first A.P and 21st term of the second A.P are 23 and 125 respectively. find two A.P.S
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2
Answer:
Let the first term of first A.P. be a and common diff. be d.
Let the the first term of second A.P. be a and common difference be 2d.
7th term =a+6d=23
a+40d=125 subtracting:-
34 d=102
d=102/34=3
a=5
first A.P.=5,8,11,14,17,20,23,......
second A.P=5,11,17,23,.....
Answered by
1
Let AP1 be a,a+d,a+2d,......
AP2 be a,a+D,a+2D,.....
given,7th term of AP1=23.......eq 1
21st term of AP2=125........eq2
eq1-eq2
this implies,a+6d-a-20D
=6d-20D=23-125
=6d-20D=-102
=20d-6d=102
as ratio of common difference is 1:2,let d=d and D =2d
=20(2d)-6d=102
40d-6d=102
34d=102;17d=51
d=3
a7=a+6d=23
a+18=23;a=5
AP1=5,8,11,14,......
D=2d=6
AP2=5,11,17,.....
hope this helps u...
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