Question

the first,third,fourth team of a proportion are 7,63,90, find the second term​

Answer 1

second no. be 10

Step-by-step explanation:

let the second no. be x

then,7:x::63:90

63x=90x7

x=90x7/63

x=10

Answer 2

Given :-

First term = 7

Third term = 63

Fourth term = 90

• The first , second , third and fourth term are in proportion .

Solution :-

Let the second term be x

Now, It is given that terms are in proportion .

7 : x :: 63 : 90

Therefore,

The product of extreme terms = 7 * 90

The product of means = 63 * x

However ,

63 * x = 7 * 90

x = 7 * 90 / 63

x = 10

Therefore , The second term is 10

• Extreme terms are the first and last proportion .

• Mean terms are the middle proportions .