Question

The first third of a 75-mile trip took twice as long as the rest of the trip. If the first third took h hours, what was the average speed, in miles per hour, for the whole trip?​

Answer 1

The given information is that the whole of the trip of 75 miles was covered in h h/2 hours, or 3h/2 hours. How can this be right as it should be 2h h or 3h, because first third of a 75-mile trip took twice(2h) as long as the rest (h)??

Step-by-step explanation:

please like And rate my ans

Answer 2

Answer:

The average speed is $\frac{50}{h}$ miles/hr.

Step-by-step explanation:

According to the question,

Total distance = 75 mile

One third of the distance, i.e. 25 miles is covered in 'h' hours.

As it is given that 25 miles took twice the time required to cover the remaining 50 miles,

=> Time required to cover the next 50 miles = h /2

We know that Average Speed = $\frac{Total Distance}{Total Time}$

                                                   = $\frac{75}{h+\frac{h}{2} }$

                                                   = $\frac{75}{\frac{3h}{2} }$

                                                   = $\frac{150}{3h}$

                                                   = $\frac{50}{h}$

Therefore, the average speed is $\frac{50}{h}$ miles/hr.