Question

The first three term of a sequence are given: 2,8,14. Find the 35th term?

Answer 1

a=2
d=6
n=35
An=?

We know that

An= a+(n-1)d

An=2+(35-1)6

An=2+34×6

An=2+204

An=206

Answer 2

here is your answer mate. .....

given a1 = 2 then D = a2-a1= 8-2 = 6

then using formula

$an \: = a + {(n - 1) d$

putting values....

here n = 35

then...

a35 = 2 + (35-1)6 = 2+204 = 206 ans

hope it helps you...