Question

The first three terms of an A.p respectively are 3y-1,3y+5,and 5y+1 find value of y​

Answer 1

Answer:

a = 3y-1.

a+d = 3y+5 .......1

a+2d = 5y+1........2

put a in (1)

3y-1+d = 3y+5

3y-3y+d=5+1

d=6

put d in (2)

3y-1+2×6 = 5y +1

3y -1+12 =5y+1

11 -1. =. 5y-3y

10 = 2y

y=5

FIRST TERM = 3×5 -1. 15-1. 14

SECOND TERM = 3×5+5. 15+5. 20

THIRD TERM =. 26