Question

the first three terms of an AP is 3y-7 , 3y+5 and 5y+1 find y.
plzz answer fast...

Answer 1

$\large\underline{\underline\mathsf\blue{QUESTION}}$

the first three terms of an AP is $\bold{3y-7 , 3y+5 \:and\: 5y+1\: find\: y.}$

$\large\underline{\underline\mathsf\green{SOLUTION}}$

GIVEN

• First three term of an AP.

1. 3y - 7
2. 3y + 5
3. 5y + 1

TO FIND

• Value of y

$\large\bold{ACCORDING\: TO\:QUESTION}$

$\bold{\implies 2(3y+5) = 3y-1 +5y +1}$

$\bold{\implies 6y +10 = 8y}$

$\bold{\implies 10 = 8y - 6y}$

$\bold{\implies 10 = 2y}$

$\bold{\implies \frac{10}{2}= y}$

$\bold{\implies 5 = y}$

Value of y = 5.