Question

The first three terms of an AP respectively are 3y-1, 3y+5 and 5y+1. Then y equals

Answer 1

Answer:

Step-by-step explanation:

3y+5-(3y-1) = 5y+1-(3y+5)

6 = 2y-4

Y= 5

So the three terms are 14,20,26

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Answer 2

Answer:

Required value of y is 5.

Step-by-step explanation:

Let us take an example :

First term of an AP be a & common difference between the APs be d.

First term = a

Second term = a + d

Third term = a + 2d

Here,

We found : 2nd term - 1st term = 3rd term - 2nd term = a + d - a = d = a + 2d - a - d = d

Result : We found that the difference between any two consecutive terms remains same.

Apply the same here :

= > Difference between 5y + 1 & 3y + 5 = Difference between 3y + 5 & 3y - 1

= > 5y + 1 - ( 3y + 5 ) = 3y + 5 - ( 3y - 1 )

= > 5y + 1 - 3y - 5 = 3y + 5 - 3y + 1

= > 2y - 4 = 6

= > 2y = 10

= > y = 5

Hence the required value of y is 5.