The first three terms of an arithmetic progression are -25, -22 and -19. Find the smallest value of n such that the nth term is positive.
Answers
Answered by
0
Answer:
-25
Step-by-step explanation:
in a number line negetive is less than positive
ex: -1 is greater than -4 because it is less ok
Answered by
1
Answer:
n=10
Step-by-step explanation:
t1=-25, t2=-22, t3=-19
a=t1=-25, d= t2-t1 =-22+25=3
tn= a+(n-1)d
tn = -25+(n-1)*3 = -28+3n
tn =-28+3n
tn=0
-28+3n=0, 3n=30
3n=30, n=10
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