The first three terms of an arithmetic progression are 3h, k, h+2.
(a) Express k in terms of h.
(b) Find the 10th term of progression in term of h.
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Since the sequence is arithmetic, there is a number
d
(the "common difference") with the property that
5
k
−
2
=
(
2
k
+
3
)
+
d
and
10
k
−
15
=
(
5
k
−
2
)
+
d
. The first equation can be simplified to
3
k
−
d
=
5
and the second to
5
k
−
d
=
13
. You can now subtract the first of these last two equations from the second to get
2
k
=
8 , implying that k=4
.
Alternatively, you could have set
d=3k−5=5−13 and solved for k=4 that way instead of subtracting one equation from the other.
It's not necessary to find, but the common difference
d=3k−5=3⋅4−5=7
. The three terms in the sequence are 11, 18, 25.
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