Question

The first three terms of an arithmetic sequence are 2k+3, 5k-2 and 10k-15, how do you show that k =4?

Answer 1

In A.P. 2b=a+c, 2(5k-2)=2k+3+10k-15, 10k-4=12k-12, 2k=8, k=4 thisis your right answer ok