the first three terms of AP ate 3y-1, 3y+5, 5y+1 find the value of y
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to be an ap the common difference will be same
T2-T1= T3-T2
3y+5-(3y-1)=5y+1-(3y+5)
3y+5-3y+1=5y+1-3y-5
6=2y-4
2y=10
y=5
T2-T1= T3-T2
3y+5-(3y-1)=5y+1-(3y+5)
3y+5-3y+1=5y+1-3y-5
6=2y-4
2y=10
y=5
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