Question

the first three terms of sequence of nth term n^2-2n-1 are​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Given:

\begin{gathered}T_n = n^2 - 2n \\\\\end{gathered}

T

n

=n

2

−2n

To Find:

The first 3 terms.

\begin{gathered}\\\end{gathered}

Find the first term:

We can find the first term by substituting n = 1 into the equation.

T_n = n^2 - 2nT

n

=n

2

−2n

T_1 = (1)^2 - 2(1)T

1

=(1)

2

−2(1)

T_1 = 1 - 2T

1

=1−2

\begin{gathered}T_1 = -1 \\\\\end{gathered}

T

1

=−1

Find the second term:

We can find the second term by substituting n = 2 into the equation.

T_n = n^2 - 2nT

n

=n

2

−2n

T_1 = (2)^2 - 2(2)T

1

=(2)

2

−2(2)

T_1 = 4 - 4T

1

=4−4

\begin{gathered}T_1 =0 \\\\\end{gathered}

T

1

=0

Find the third term:

We can find the second term by substituting n = 3 into the equation.

T_n = n^2 - 2nT

n

=n

2

−2n

T_1 = (3)^2 - 2(3)T

1

=(3)

2

−2(3)

T_1 = 9 - 6T

1

=9−6

\begin{gathered}T_1 =3 \\\\\end{gathered}

T

1

=3