Question

the first three terms of sequence when nth terms tn is n^2-2n

Answer 1

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Answer 2

Given:

$T_n = n^2 - 2n$

To Find:

The first 3 terms.

Find the first term:

We can find the first term by substituting n = 1 into the equation.

$T_n = n^2 - 2n$

$T_1 = (1)^2 - 2(1)$

$T_1 = 1 - 2$

$T_1 = -1$

Find the second term:

We can find the second term by substituting n = 2 into the equation.

$T_n = n^2 - 2n$

$T_1 = (2)^2 - 2(2)$

$T_1 = 4 - 4$

$T_1 =0$

Find the third term:

We can find the second term by substituting n = 3 into the equation.

$T_n = n^2 - 2n$

$T_1 = (3)^2 - 2(3)$

$T_1 = 9 - 6$

$T_1 =3$

Answer: The first 3 terms are -1, 0 and 3