Question

the first three terms of the sequence tn=4n2+3

Answer 1

put n=1 u ill get first term and sequenced put other values

Answer 2

Answer:

3, 7 and 19

Step-by-step explanation:

We have been given the sequence

$t_n=4n^2+3$

In order to find the first three terms of the sequence, plug n=0,1,2

For n=0

$t_0=4(0)^2+3\\\\t_0=3$

For n=1

$t_1=4(1)^2+3\\\\t_1=7$

For n=2

$t_2=4(2)^2+3\\\\t_1=19$

Therefore, the first three terms of the sequence is given by

3, 7 and 19