Math, asked by retheesh6265, 5 months ago

The first two digits of a 4-digit number is the
LCM of 4 and 7. The third digit is zero and the last
digit is the square of 3. Find the square root of the
4-digit number.​

Answers

Answered by shilshaurya5606
1

Answer:

53 is the square root of the number (it is 2809)

Step-by-step explanation:

LCM of 4 and 7 = 28

Thus, first 2 digits of the 4 digit number are 28.

Third digit  = 0 (given)

Last digit = 3² => 9

∴ Number is 2809.

And the square root of 2809 = √2809 => 53

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