Question

The first two terms of a geometric sequence are a1 = 1⁄3 and a2 = 1⁄6. What is a8, the eighth term?

Answer 1

a2-a1=1/6-1/3=-1/6

a8=a+(n-1)d

1/3+(8-1)-1/6

1/3_7/6

=-5/6