The First two terms of an AP are 2 and -3. Its 20th term is
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a1=2
a2= -3
d= a2-a1
= -3-2
=-5
an= a+ (n-1) d
a20= a+ 19d
= 2+ 19(-5)
2-95
-93
-93 is the ans
Answered by
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Answer:
The 20th term of the given AP is -93.
Step-by-step explanation:
Given:
First term (a1) = 2
Second term (a2) = -3
To find:
20th term (a20)
Solution:
It is given that the terms are in AP.
Common difference (d) = a2 - a1
d = -3 - 2
d = -5
The nth term of an AP is given as
tn = a1 + (n-1)d
tn = 2 + (n-1)(-5)
tn = 2 - 5n + 5
tn = 7 - 5n
When n = 20,
t20 = 7 - 5(20)
t20 = 7 - 100
t20 = -93
Therefore, the 20th term is -93.
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