Math, asked by LeStickBug, 3 months ago

The first two terms of an arithmetic sequence are 1/8 and 19/24. What is the difference between every pair of consecutive terms in the sequence?

Answers

Answered by Anonymous
2

Answer:

Have a look at 1/8 and 19/24. Convert 1/8 to 3/24. Note that 19/24 is obtained by adding 16/24 to 3/24. Thus, the common difference is 16/24, or 8/12, or 4/6, or 2/3.

Answered by tennetiraj86
2

Step-by-step explanation:

Given:-

The first two terms of an arithmetic sequence are 1/8 and 19/24.

To find:-

What is the difference between every pair of consecutive terms in the sequence?

Solution:-

Given that

The first two terms of an A P = 1/8 and 19/24

First term = 1/8

Second term = 19/24

Since they are in the AP then the common difference between the two consecutive terms is equal or same throughout the sequence

=> Common difference = (19/24)-(1/8)

=>d = (19-3)/24

(Since LCM of 24 and 3 is 24)

=>d= 16/24 or 2/8

Answer:-

The difference between every pair of consecutive terms in the sequence is 16/24 or 2/8

Used formula:-

In an AP , a is the first term and d is the common difference then d = an - an-1

Where, an is the nth term and an-1 is the (n-1)th term of the AP.

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