Question

The fission properties of Pu are very similar to those of U.
The average energy released per fission is 180 Mev. How much energy, in Mev, is
released if all the atoms in 1 kg of pure "Pu undergo fission?​

Answer 1

Answer:

Number of atoms in 1 kg of pure Pu=

239

6.023×10

23

×1000=2.52×10

24

As average energy released in fission is 180MeV, the total energy released is

⇒2.52×10

24

×180MeV

⇒4.53×10

26

MeV.