Question

the five angle of a pentagon are in the ratio 5,6,7,8,9,10. find all the angles

Answer 1

heyy!!
let the angle be 5x,6x,7x,8x,9x,10x
sum of angles of a pentagon =540
therefore, 5x+6x+7x+8x+9x+10x = 540
45x = 540
x = 540/45
x = 12
so , 5x = 5*12=60
6x = 6*12=72
7x = 7*12= 84
8x = 8*12=96
9x = 9*12 =108
10x=10*12=120
hope it will help:-)

Answer 2

Let the ratio be x

By using angle sum property of pentagon

5x+6x+7x+8x+9x+10x = 540

45x = 540

x = 540/45

x = 12

Therefore ,

5x = 5 *12=60

6x=6*12=72

7x=7*12=84

8x=8*12=96

9x=9*12=108

10x=10*12=120

Hope it will help for everyone ☺️