The five angles of a pentagin are in the ratio 1:2:3:4:5. Find the angles.
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Answered by
1
total angles of a pentagon = 360
let angles be x,2x,3x,4x,5x.
x + 2x + 3x + 4x + 5x = 360
15x = 360
x = 14
Each angle :
1st angle = x = 14
2nd angle = 2x = 28
3rd angle = 3x = 42
4th angle = 4x = 56
5th angle = 5x = 70
let angles be x,2x,3x,4x,5x.
x + 2x + 3x + 4x + 5x = 360
15x = 360
x = 14
Each angle :
1st angle = x = 14
2nd angle = 2x = 28
3rd angle = 3x = 42
4th angle = 4x = 56
5th angle = 5x = 70
KINGAMAN:
wrong
Answered by
1
Let the angles be x
SUMOF ALL ANGLES IN REGULAR PENTAGON =540°
then,
x+2x+3x+4x+5x=540
15x=540
x=540÷15
x=36
1 st angle=x=36°
2 nd angle=2x=2×36°=72°
3 rd angle=3x=3×36°=108°
4th angle=4x=4×36°=144°
5 th angle=5x=5×36°=180°
[||PROOF||]
SUM OF ANGLES IN REGULAR PENTAGON=540°
X°+2X°+3X°+4X°+5X°=540°(X°=36°)
36°+72°+108°+144°+180°=540°
540°=540°
【PROOVED】
SUMOF ALL ANGLES IN REGULAR PENTAGON =540°
then,
x+2x+3x+4x+5x=540
15x=540
x=540÷15
x=36
1 st angle=x=36°
2 nd angle=2x=2×36°=72°
3 rd angle=3x=3×36°=108°
4th angle=4x=4×36°=144°
5 th angle=5x=5×36°=180°
[||PROOF||]
SUM OF ANGLES IN REGULAR PENTAGON=540°
X°+2X°+3X°+4X°+5X°=540°(X°=36°)
36°+72°+108°+144°+180°=540°
540°=540°
【PROOVED】
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