Question

The five-digit number 24A8B is divisible by 4, 5, and 9. How do you determine it?

Answer 1

ANSWER:

If the no. is divisible by 4,then last two digit should be divisible by 4 I.e. 80

now, the no. is divisible by 5 since, last digit is 0.

If the no. is divisible by 9,then sum of digit should be divisible by 9 . if we take A=4 then sum of digit is 2+4+4+8+0 =18 which is divisible by 9.

therefore, The no. is 24480.

Answer 2

Answer:4

Step-by-step explanation: