Question

the five successive measurements of the thickness of a glass plate using a screw gauge

1.56 mm,1.55 m m, 1.54 mm, 1.57 m m ,and 1.53 m m. Evaluate 1) the mean value of the

thickness 

2) The absolute error in each measurement.

 3) The mean absolute error 

4)  The relative error

 5 )The  percentage error​

Answer 1

Explanation:

${ {3}^{2} }^{3}  \times  {(2 \times  {3}^{5}) }^{ - 2}  \times  {18}^{2 }  \\  \\  =  {3}^{6}  \times  \frac{1}{4 \times  {3}^{10} }  \times  {18}^{2}  \\  \\  =  \frac{ {18}^{2} }{4 \times  {3}^{4} }  \\  \\  =  \frac{ \cancel{18 } \: ^{ \cancel{6}} \: ^{ \cancel{2}}\times { \cancel{18}}  \: ^{ \cancel{6 }} \:  ^{ \cancel{2}} \:  ^1 }{ { \cancel{4 }\:_1}\times { \cancel{3} \: _1} \times { \cancel{3 } \: _1}\times { \cancel{3} \:_1} \times { \cancel{3} \: _1} }  \\  \\  = { \huge{ \red{ \boxed{1}}}}$