Question

The fixed ends of vibrating string is called

Answer 1

Answer:

Since the point at a distance of L/4 from an end vibrates with maximum displacement, the frequency of vibration is of the second order.

Hence, 2f

0

=100Hz

where f

0

is the fundamental frequency.

⟹f

0

=50Hz

Now the next smallest mode under which the point again becomes point of maximum displacement is the 6th order.

Hence, frequency under this mode=6f

0

=6×50Hz=300Hz

Answer 2

Antinodes.

The fixed ends of vibrating string is called a antinodes.

• Because a crest will collide with a crest during a full cycle of vibration and a trough will collide with a trough after a half cycle, antinodes are constantly bouncing back and forth between these regions of significant positive and big negative displacement.
• On a standing wave, a node is a position that holds steady throughout time. It results from two waves interfering negatively with one another. The particle wave with the greatest amplitude is called the antinode wave.
• Nodes and antinodes are present in every standing wave pattern. The destructive interference of the two waves results in the nodes, which are points of no displacement. The antinodes experience maximal displacement from the rest position as a result of the constructive interference of the two waves.
• Pressure changes cause sound to be created, and where pressure changes the most, the sound is louder. Because the pressure is highest and the strain is greatest there, the sound is louder there.

#SPJ2