Question

The flat bar shown is 10 mm thick and is pulled by a force p producing a total change in length of 0.2 mm. Determine the maximum stress developed in the bar. Take e= 200 gpa

Answer 1

Answer:

P=14.285 KN

Explanation:

Formula for calculation of change in length of material stress is applied to it;

Delta =(Length of Material)/(Height of Material) x P/E

Total change in length of the bar is made up of three components and this is given by

0.2x10^3 =[0.3/0.025x0.01+  0.3/0.05x0.01 + 0.25/0.025x0.01]x P/(200x10^9)

P=14.285 KN

Answer 2

Answer:

P=14.285 KN

Explanation:

according to the question

Formula for calculation of change in length of material stress is applied to it;

$Delta$ = $\frac{Length of Material}{Height of Material}\times \frac{P}{E}$

Total change in length of the bar is made up of three components and this is given by

${0.2}\times 10^3$ = $\frac{0.3}{0.025}\times 0.01$ +  $\frac{0.3}{0.05}\times 0.01$ +$\frac{0.25}{0.025}\times 0.01]\times \frac{P}{200\times 10^9}$

P=14.285 KN

Hence, the value of P is 14.285 KN.