Question

The floor and four walls of a cubical auditorium of side 85 m is to be tiled. If the side of each square tile is 17 cm, how many tiles will be , required to tile the auditorium? Calculate the total cost if each tile costs rupees 56.50 percent. ​

Answer 1

Side of cubic room = 85m

Area of 4 walls + floor = 5a² = 5 ×85 ×85 = 36125 m² = 361250000 cm²

Side of tile = 17cm

Area of tile = a² = 17× 17 = 289 cm²

Total no. of tiles required = Area of 4 walls + Room/ Area of Tile = 361250000/289

= 1250000 tiles

Cost of one tile = 56.5 rupees

Coat of 1250000 tiles = 1250000 × 56.5

= 7062500 rupees

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