Question

The floor area of a conical canvas tent is 154m2 . If the volume of the tent 513 1/3 m2 ;find the area of canvas needed ​

Answer 1

Answer:

Floor area of conical tent = 154 sq.m.

Height = 24 m

Since, floor of conical tent is circular

So, area of floor = πr

2

So, πr

2

= 154

⟹

7

22

r

2

=154

⟹r

2

=

22

7

×154

⟹r

2

= 49

⟹r=7

Also, we know that

slantheight

2

=height

2

+radius

2

i.e., l

2

=h

2

+r

2

i.e., l

2

=24

2

+7

2

i.e., l

2

=576+49

i.e., l

2

=625

i.e., l=25

So, canvas required = curved surface area of the conical tent

= πrl

=

7

22

×7×25

= 22×25

= 550 sq.m.

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Answer 2

Step-by-step explanation:

Floor area of conical tent = 154 sq.m.

Height = 24 m

Since, floor of conical tent is circular 

So, area of floor = πr2

So,  πr2 = 154

⟹722r2=154

⟹r2 = 227×154

⟹r2 = 49

⟹r=7

Also, we know that

slantheight2=height2+radius2

i.e., l2=h2+r2

i.e., l2=242+72

i.e., l2=576+49

i.e., l2=625

i.e., l=25

So, canvas required = curved surface area of the conical tent 

                                  = πrl

                                  = 722×7×25         

                                  = 22×25     

                                  = 550 sq.m