Question

The floor of a bathroom is 5 m long and 3 m 50 cm wide. It is to be covered completely by square tiles of side 25 cm. Find the cost of the tiles at the rate of ₹60 per tile. ​

Answer 1

$\large\underline{\sf{Solution-}}$

Given that,

Length of bathroom floor, L = 5m = 500 cm

Breadth of bathroom floor, B = 3 m 50 cm = 350 cm

We know,

$\boxed{\sf{ \: \: Area_{(rectangle)} \: = \: Length \times Breadth \: \: }}$

So, using this result, we get

$\rm \: Area_{(floor)} \: = \: 500 \times 350 = 175000 \: {cm}^{2}$

Now,

Side of square tile = 25 cm

We know,

$\boxed{\sf{ \: \: \: Area_{(square)} = {(side)}^{2} \: \: }}$

So, using this result,

$\rm \: Area_{(tile)} = {25}^{2} = 625 \: {cm}^{2}$

Let assume that number of tiles used be n.

So,

$\rm \: n \times Area_{(tile)} = Area_{(floor)}$

$\rm \: 625n = 175000$

$\rm \: n = \dfrac{175000}{625}$

$\rm\implies \:n \: = \: 280$

Now, Further given that

Cost of 1 tile = ₹ 60

So,

Cost of 600 tiles = ₹ 60 × 280 = ₹ 16800

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

$\begin{gathered}\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Base\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}d\sqrt {4a^2-d^2}\\ \\ \star\sf Parallelogram =Base\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}\end{gathered}$

Answer 2

Question:-

The floor of a bathroom is 5 m long and 3 m 50 cm wide. It is to be covered completely by square tiles of side 25 cm. Find the cost of the tiles at the rate of ₹60 per tile.

Given:-

• Bathroom is 5m, long and 3m 50cm wide.
• Square tiles of side 25cm.
• cost of the tiles at the rate of ₹60 per tile.

To Find:-

• Cost of the tiles.

Solution:-

☆ Floor Area = length × breadth ☆

• l = 5m.
• b = 3.5m.

Floor Area = 5 × 3.5 = 17.5m².

Tiles Area = (0.25)² = 0.0625m² .

$\sf \large No.of \: tiles = \frac{Floor \: Area}{Tiles Area} = {{ \cancel{\frac{17.5}{0.0625} }}}$

No. of tiles = 280.

Cost of tiles = 280 × 60

Cost of tiles = ₹16,800.

Answer:-

${ \boxed{ \sf \large \color{springgreen}\therefore Cost \: of \: the \:tiles = ₹16,800.}}$

Hope you have satisfied. ⚘