THE FLOOR OF A BUILDING CONSIST OF 3000 TILES WHICH ARE RHOMBUS SHAPED AND EACH OF ITS DIAGONALS ARE 45 cm & 30 cm IN LENGTH. FIND THE ....
AREA OF ONE TILE.
AREA OF 3000 TILES.
COST OF POLISHING THE FLOOR AT THE RATE OF Rs.4 / sq.m
Answers
Answer:
Step-by-step explanation:
Mensuration:
Mensuration is the branch of mathematics which concerns itself with the measurement of Lengths, areas & volume of different geometrical shapes or figures.
Plane Figure: A figure which lies in a plane is called a plane figure.
For e.g: a rectangle, square, a rhombus, a parallelogram, a trapezium.
Perimeter:
The perimeter of a closed plane curve is the total length of the curve.
Unit of perimeter is a unit of length.
Area: the area of the plane figure is the surface enclose by its boundary.
A square centimetre (cm²) is generally taken at the standard unit of an area. We use square metre (m²) also for the units of area.
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Solution:
Given:
d1= 45cm , d2= 30cm
Number of tiles= 3000
Rate per m²= ₹4
Area of Rhombus= 1/2×d1×d2
= (1/2) × 45 × 30=675
Area of 1 tile= 675 cm² = 675/10000 m²
Area of 3000 tiles= 3000 × (675/10000)
[1cm²= 1/10000m²]
cost of Polishing the floor
= Total Area × rate
= (3000 × 675 ×4)/10000
= 3× 675×4/10
= 3× 67.5×4
= 12× 67.5
= ₹ 810
Hence the total cost of polishing the floor = ₹ 810
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Hope this will help you...