Question

the floor of a building consist of 4000 tiles which are rhombus shaped and each of its diagonal are 45 cm40 cm in length find the total cost of polishing the floor if the cost per metre square is rupees 5​

Answer 1

Answer:

Solution: Length of one diagonal, d1 = 45 cm and d2= 30 cm

Area of one tile = 1/2 d1 d2

= ½ x 45 x 30 = 675

Area of one tile is 675 cm^2

Area of 3000 tiles is

= 675 3000 = 2025000 cm^2

=2025000/ 10000

= 202.50 m^2

Cost of polishing the floor per sq. meter = 4

Cost of polishing the floor per 202.50 sq. meter = 4 x 202.50 = 810

Hence the total cost of polishing the floor is Rs. 810.

`

Answer 2

Step-by-step explanation:

area of 1 rhombus shape tile = 1/2 90×60= 2700m²

area of rhombus shape tile = 6000× 1/2 × 90× 60= 6000

total cost of polishing = 6000 × 2700× 5= rs/- 81,000,000