Question

The floor of a building consists around 20 tiles which are rhombus shaped and each
of its diagonals are 45cm and 3cm in length. Find the total cost of flooring if each tile
cost rupees 3 per cm²​

Answer 1

Step-by-step explanation:

Area of each rhombic tile = 1/2 × product of diagonals

= 1/2 × 45 × 3 cm²

Area of the floor = 20 × Area of 1 tile = 20/2 × 45× 3 cm²

= 2150 cm²

Cost of flooring = 2150 × 3 = Rs.6450

Answer 2

Answer:

• Number of rhombus shaped tiles = 20
• Diagonals of each tile = 45 cm and 3 cm
• Rate of each tile = Rs. 3 per cm²
• Cost of tiling the floor = ?

To find the cost of tiling, first we will find Area of Each tiles and then Multiply it with Rate.

• Area of 20 rhombus shaped tile :

⇒ Area = (½ × D₁ × D₂) × Number of tiles

⇒ Area = (½ × 45 × 3) × 20

⇒ Area = ½ × 45 × 3 × 20

⇒ Area = 45 × 3 × 10

⇒ Area = 1350 cm²

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• Cost of tiling the floor :

⇢ Cost = Area of tiles required × Rate

⇢ Cost = 1350 cm² × Rs. 3 per cm²

⇢ Cost = 1350 × Rs. 3

⇢ Cost = Rs. 4050

∴ Cost of tiling the floor is Rs. 4050.