Question

the floor of a building consists condition after 3000 tiles which are Rhombus shaped the diagonal of each of the tiles are 45 and 30 cm find the total cost of polished that if cost per to M2 is rupees 2.50

Answer 1

Here is your answer...

Answer 2

area of floor = 3000 × ( area of Rhombus )
$=3000 \times \frac{1}{2} \times digonal \: first \: \times diagonal \: second$
$= 3000 \times \frac{1}{2} \times 45 \times 30 \\ = 3000 \times 675 \\ = 202500 \: {cm}^{2}$
cost = area × rate
= 202500 × 2.50
= rs. 506250
please mrk it as brainliest please