Question

The floor of a building consists of 1200 tiles which are trapezium shaped with 45cm

and 25cm as its parallel sides and 20cm as its height. Find the cost of polishing the

floor at the rate of Rs. 4.50.​

Answer 1

$\underline{ \underline{ \Large \bf { Appropriate \; Question :} } }$

The floor of a building consists of 1200 tiles which are trapezium shaped with 45cm and 25cm as its parallel sides and 20cm as its height. Find the cost of polishing the floor at the rate of Rs. 4.50 cm².

$\underline{ \underline{ \Large \bf { Given:} } }$

• The floor of a building consists of 1200 tiles.

• Parallel sides of the trapezium = 45 cm & 25 cm

• Height of the trapezium = 20 cm

• Cost of of polishing the floor per cm² = Rs. 4.50.

$\underline{ \underline{ \Large \bf { To \: calculate:} } }$

• The cost of polishing the floor at the rate of Rs. 4.50 cm².

$\underline{ \underline{ \Large \bf { Calculation:} } }$

In order to find the cost of polishing the floor, we need to find the area of the entire floor.

According to the question,

⇒ Area of the floor = Area of 1 trapezium tile × 1200 tiles

Also,

⇒ Cost of polishing the floor = Area of the floor × Rs. 4.50

Let's find the area of the floor first !

⇒ Area of the floor = Area of 1 trapezium tile × 1200 tiles

Where,

→ Area of 1 trapezium tile = $\sf { \dfrac{1}{2} }$ × sum of parallel sides × height

→ Area of 1 trapezium tile = [ $\sf { \dfrac{1}{2} }$ × (45+25) × 20 ] cm²

→ Area of 1 trapezium tile = [ 1 × 70 × 10 ] cm²

→ Area of 1 trapezium tile = 700 cm²

So,

⇒ Area of the floor = ( 700 × 1200 ) cm²

⇒ Area of the floor = 840,000 cm²

Therefore,

⇒ Cost of polishing the floor = Area of the floor × Rs. 4.50

⇒ Cost of polishing the floor = Rs ( 840,000 × 4.50 )

⇒ Cost of polishing the floor = Rs ( 840,000 × $\sf { \dfrac{450}{100} }$ )

⇒ Cost of polishing the floor = Rs ( 8400 × 450 )

⇒ Cost of polishing the floor = Rs 3780000

Henceforth, cost of polishing the floor is Rs 3780000.

Answer 2

Given :

$\implies$The floor of a building consists of 1200 tiles.

$\implies$Parallel sides of the trapezium = 45 cm & 25 cm

$\implies$Height of the trapezium = 20 cm

$\implies$Cost of of polishing the floor per cm² = Rs. 4.50.

$\rule{315}{3}$

To Find :

$\implies$ The cost of polishing the floor at the rate of Rs. 4.50 cm².

$\rule{315}{3}$

Solution :

According to the question,

[⇒ Area of the floor = Area of 1 tile × 1200 tiles]

Also,

✰Cost of polishing the floor

⇒Area of the floor × Rs. 4.50

Let's find the area of the floor first !

⇒ Area of the floor = Area of 1 trapezium tile × 1200 tiles

Where,

→ Area of 1 trapezium tile = 1/2 × sum of parallel sides × height

→ Area of 1 trapezium tile = 1/2 × (45+25) × 20 ] cm²

→ Area of 1 trapezium tile = [ 1 × 70 × 10 ] cm²

→ Area of 1 trapezium tile = 700 cm²

So,

⇒ Area of the floor = ( 700 × 1200 ) cm²

⇒ Area of the floor = 840,000 cm²

Therefore,

⇒ Cost of polishing the floor = Area of the floor × Rs. 4.50

⇒ Cost of polishing the floor = Rs ( 840,000 × 4.50 )

⇒ Cost of polishing the floor = Rs ( 840,000 × 450/100.

⇒ Cost of polishing the floor = Rs ( 8400 × 450 )

⇒ Cost of polishing the floor = Rs 3780000

Henceforth, cost of polishing the floor is Rs 3780000.

$\rule{315}{3}$

✰✰Main Answer = Rs 3780000. ✰✰