Question

The floor of a building consists of 2000 tiles of rhombus shape.
The diagonals of each tile are 40 cm and 30 cm in length.Find
the cost of polishing the floor at the rate of ₹ 25 per sq m.
Plz Show full method​

Answer 1

35,000

Step-by-step explanation:

Area of tile (rhombus shaped) = product of diagonal

= 40×30 cm

= 70 cm sq.

Area of 2000 tiles = 2,000 × 70

= 1,40,000

If 100 cm = 1 m

then 1,40,000 cm = 1,40,000 ÷ 100

= 1,400 m sq.

Cost of polishing the floor = ₹25 × 1,400

= ₹35,000

Therefore, the cost of polishing the floor is ₹35,000

Answer 2

Answer:

6000

Step-by-step explanation:

We know, the area of a rhombus is given by the product of its diagonals. In this case, we have

$d1 = 40 \: cm \: and \: d2 = 30 \: cm$

So,

$ar(rhbs.) = (40 \times 30 ) {cm}^{2} \\ = 1200 \: {cm}^{2} = \frac{1200 }{10000} \: {m}^{2} \\ = 0.12 \: {m}^{2} \: per \: tile$

Given, there are total 2000 tiles and the cost of each square metre is Rs. 25 so,

total cost is

$2000 \: tiles \times( 0.12 \: {m}^{2}per \: tile )\times (rs. \: 25 \: per \: {m}^{2} ) \\ = rs. \: (2000 \times \frac{12}{100} \times 25 ) =rs. (\: 20 \times 12 \times 25) \\ = rs. (\: 500 \times 12) = rs. \: 6000$

So, the total cost is Rupees 6000.

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