The floor of a building consists of 3000 rhombus shaped tiles.Its sides are 50cm one of its diagonal is 60cm.Find the cost of polishing the floor at the rate of rupees 4 per m^2
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RohanJS:
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hello,
we indicate with D, d the diagonals of the rhombus; with l the side.
let's calculate the other diagonal:
D=2×√l²-(d/2)²=2×√50²-(60/2)²=2×√50²-30²=2×√2500-900
=2×√1600=2×40=80 cm
we calculate the area of rhombus:
A=(D×d)÷2=(80×60)÷2=4800÷2=2400 cm²
we calculate the area of 3000 tiles:
At=A×3000=2400×3000=7200000 cm² = 720 m²
we calculate the cost of polishing:
c=720×4=2880 rs
Thus, the cost of polishing the floor is Rs 2880.
bye :-)
we indicate with D, d the diagonals of the rhombus; with l the side.
let's calculate the other diagonal:
D=2×√l²-(d/2)²=2×√50²-(60/2)²=2×√50²-30²=2×√2500-900
=2×√1600=2×40=80 cm
we calculate the area of rhombus:
A=(D×d)÷2=(80×60)÷2=4800÷2=2400 cm²
we calculate the area of 3000 tiles:
At=A×3000=2400×3000=7200000 cm² = 720 m²
we calculate the cost of polishing:
c=720×4=2880 rs
Thus, the cost of polishing the floor is Rs 2880.
bye :-)
really thank you
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