The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45cm and 30cm in length. Find the total cost of polishing the floor if the cost per m square is Rs4
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Answer:
cost of polishing =₹810
Step-by-step explanation:
area of one tile = 1 (d1 × d2 )
2
= 1×45×30
2
=675cm^2
total surface area of floor = 675×3000
=2025000cm^2
=202.5m^2
cost of polishing = 202.5×4
₹810
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