Question

The floor of a building consists of 3000 tiles which are rhombus shaped. The diagonals of
each of the tiles are 45 cm and 30 cm. Find the total cost of polishing the floor, if cost per m2 is 2.50.​

Answer 1

Step-by-step explanation:

100cm=1m

30cm=30/100m

=0.3m

45cm=45/100

=0.45m

one tile=1/2*0.45*0.3

=0.0675m^2

3000tiles=0.0675*3000

=202.5m^2

1m^2=2.50

202.5m^2=2.50*202.5

=506.25rs

Answer 2

Question :-

The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per meter square is ₹ 4.

Given :-

• Total tiles consists building = 3000 tiles

• Tiles are in rhombus shape.

• Diagonals of tiles = 45cm and 30cm

• cost per metre square = Rs. 2.50

To find :-

• Total cost of polishing?

Solution :-

• Number of tiles = 3000

• Length of the two diagonals of a tile = 45 cm and 30 cm

Area of one tile :-

⠀⠀$= \dfrac{1}{2} \times d_{1} \times \: d_{2}$

⠀⠀$= \dfrac{1}{2} \times 45 \times \: 30$

⠀⠀$= 45 \times 15$

⠀⠀$= 675 {cm}^{2}$

________________

Area covered by 3000 tiles

= 3000 × 675 ${cm}^{2}$

= 2025000 ${cm}^{2}$

= 202.5 ${m}^{2}$

Cost of polishing the floor

= 202.5 × 4

= ₹ 810

Hence, the required cost = ₹ 810.