Question

the floor of a building consists of 3000 tiles which are Rhombus shaped and each of its diagonals are 45 cm and 30 cm in length find the total cost of polishing the floor​

Answer 1

Step-by-step explanation:

Since area of rhombus is diagonal1 *diagonal2/2

Area of each rhombus tile is 45*30/2=675

There are such 3000 tiles so total area is no.of tile*area of each tile

So total area= 3000*675=202500

Since you have not specified cost of polishing the floor, so the answer should be 202500*cost of polishing per unit Sq.

Answer 2

Cost of polishing = Rs. 810

Step-by-step explanation:

Given:

• Diagonals of the rhombus = 45 cm and 30 cm
• Total number of tiles = 3000
• Cost of polishing = Rs. 4 per m²

To Find:

• The total cost of polishing all the tiles

Solution:

• First finding the area of a rhombus shaped tile.

Area of a rhombus is given by,

$\boxed{\tt Area\:of\:a\:rhombus=\dfrac{d_1\times d_2}{2}}$

where d₁ is the first diagonal,

d₂ is the second diagonal

Substitute the data,

Area of the tile = (45 × 30)/2

⇒ 1350/2

⇒ 675 cm²

Hence the area of each tile is 675 cm².

Therefore,

Area of 3000 tiles = 3000 × Area of 1 tile

⇒ 3000 × 675

⇒ 2025000 cm² = 202.5 m²

Now the total cost of polishing is given by,

Cost of polishing = Area of the tiles × Rate per m²

⇒ 202.5 × 4

⇒ 810 rupees

Hence the total cost of polishing the floor is 810 rupees.