Question

the floor of a building consists of 3000 tiles which are rhombus shaped on each of its diagonals are 45 cm and 30 cm in length find the total cost of polishing the floor if the cost per metre square is rupees 4

Answer 1

area of each tiles = 1/2 *.45×.3 m^2 =.135/2m^2
" " 3000 tiles = 405 m^2/2
total cost= rs. 405/2 *4 =rs. 810 (ans)

Answer 2

1/2×45×30
area of each tile=675sq.cm
675×3000
area of 3000 tiles=2025000sq.cm
=20250sq.m
=20250×4
=81000RS.