Question

the floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonal are 45 cm and 30 cm in length. find the total cost of polishing the floor,if the cost per square meter is rs.4​

Answer 1

Answer:

Rupees 810

Explanation:

given,

total number of tiles used=3000

since tile is in the shape of rhombus and diagnoals are 45cm and 30cm

thus,

D1=45cm

D2=30cm

therefore,

area of one tile=area of rhombus

=1/2*d1*d2

=1/2*30*45

=15*45

=675square.cm

area of one tile is 675square.cm

so,the area of 3000tiles = 3000*675

= 2025000square.cm

now, we need to find the cost and for that we need to convert area from cm to m

area in meter=2025000(1/100)m.square

=2025000/10000 metre.square

=202.5metre.square

now cost of polishing 1 metre.square=4

cost of polishing 202.5metre.square=202.5*4

=(2025/10)*4

=(405/2)*4

=405*2

=rs 810

therefore,the total cost of polishing is =rs 810

Answer 2

Cost of polishing = Rs. 810

Step-by-step explanation:

$\sf\red{given :-}$

Diagonals of the rhombus = 45 cm and 30 cm

Total number of tiles = 300

Cost of polishing = Rs. 4 per m²

$\sf\blue{to\:find :-}$

The total cost of polishing all the tiles

$\sf\green{solution :-}$

First finding the area of a rhombus shaped tile.

Area of a rhombus is given by,

$\boxed{\tt Area\:of\:a\:rhombus=\dfrac{d_1\times d_2}{2}}$

where d₁ is the first diagonal,

d₂ is the second diagonal

Substitute the data,

Area of the tile = (45 × 30)/2

⇒ 1350/2

⇒ 675 cm²

Hence the area of each tile is 675 cm².

Therefore,

Area of 3000 tiles = 3000 × Area of 1 tile

⇒ 3000 × 675

⇒ 2025000 cm² = 202.5 m²

Now the total cost of polishing is given by,

Cost of polishing = Area of the tiles × Rate per m²

⇒ 202.5 × 4

⇒ 810 rupees

Hence the total cost of polishing the floor is 810 rupees.