Question

the floor of a building consists of 3000 tiles which are rhombus shaped. the diagonals of each of the tiles are 45cm and 30cm. find the total cost of polishing the floor,if the cost per m^2 is Rs. 4​

Answer 1

Step-by-step explanation:

Given:-

• The floor of a building consists of 3000 tiles.

• The tiles are in the shape of a rhombus.

• The diagonals of the rhombus are 45cm and 30cm.

To Find:-

• The total cost of polishing the floor, if the cost per m² is Rs. 4

Solution:-

The tiles are in the shape of a rhombus.

Total number of tiles = 3000

One of the diagonals of rhombus = 45cm

The other diagonal = 30cm

$\rm Area \: of \: rhombus = \dfrac{1}{2} \times d_{1} \times d_{2}$

• Here, $\rm d_{1} \: and \: d_{2}$ are the diagonals of the rhombus.

Area of 1 tile = ½ × 45 × 30

= 45 × 15

= 675

Area of 1 tile = 675cm²

Area of 3000 tiles = 675 × 3000 =2025000 cm²

1 cm² = 1/10000 m²

2025000cm² = 2025000/10000 = 202.5m²

Given, cost per m² = Rs. 4

Cost for 202.5m² = 4 × 202.5 = Rs.810

$\underline{\boxed{\purple{\rm \therefore The \: cost \: of \: polishing \: the \: floor = Rs. 810}}}$