Question

the floor of a building consists of 3000 tiles which are rhombus shaped. The diagonals of each of the tiles are 45cm and 30cm. find the total cost of polishing the floors ,if cost per m2isтВ╣2.50.

Answer 1

Area of a tile sha67ped rhombus = 1/2×diagonal1 ×diagonal 2

=1/2 ×45×30
=675cm^2
1m^s=10000cm
?m^s=675cm
675/10000=0.0675m^2
area of 1 tile=0.0675m^2
area of 3000tiles=0.0675×3000=202.5m^2
Total expense = 202.5×2.50=506.25 rupees

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Answer 2

Answer:

Area of a tile sha67ped rhombus = 1/2×diagonal1 ×diagonal 2

=1/2 ×45×30

=675cm^2

1m^s=10000cm

?m^s=675cm

675/10000=0.0675m^2

area of 1 tile=0.0675m^2

area of 3000tiles=0.0675×3000=202.5m^2

Total expense = 202.5×2.50=506.25 rupees