The floor of a building consists of 3000 tiles which are rhombus shaped and each of is diagonals are 45cm and 40cm in length find the total cost of polishing the floor if the cost per square is RS 4
Answers
Answered by
1
Area of a tile sha67ped rhombus = 1/2×diagonal1 ×diagonal 2
=1/2 ×45×40
=900cm^2
1m^s=10000cm
?m^s=900cm
900/10000=0.09m^2
area of 1 tile=0.09m^2
area of 3000tiles=0.09×3000=270m^2
Total expense = 270×4=1080 rupees
If you find it helpful please mark it as brainliest ..
=1/2 ×45×40
=900cm^2
1m^s=10000cm
?m^s=900cm
900/10000=0.09m^2
area of 1 tile=0.09m^2
area of 3000tiles=0.09×3000=270m^2
Total expense = 270×4=1080 rupees
If you find it helpful please mark it as brainliest ..
Answered by
2
★GIVEN:-
Total Number of tiles used = 3000
Tiles is in the shape of rhombus
Diagonals are d1 = 50cm, d2 = 40cm
Cost per metre = Rs.4
★TO FIND:-
Total cost of polishing the floor
★FORMULA USED:-
★SOLUTION:-
Area of 1 tile = Area of Rhombus
Area of 3000 tiles = 3000 × Area of 1 tile
= 3000 × 1000
= 30,00,000cm^2
Now, we will find the cost.
Since, cost is given per m^2
we need to convert the area into m^2
Area = 30,00,000cm^2
Similar questions