the floor of a building consists of 3000 tiles which are Rhombus shaped and each of its diagonal are 45 cm and 30 cm in length find the total cost of polishing the floor if the cost per metre square is 4
Vodka madam ans kre xD xD (ー_ー゛)
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Cost of polishing = Rs. 810
Step-by-step explanation:
Diagonals of the rhombus = 45 cm and 30 cm
Total number of tiles = 300
Cost of polishing = Rs. 4 per m²
The total cost of polishing all the tiles
First finding the area of a rhombus shaped tile.
Area of a rhombus is given by,
where d₁ is the first diagonal,
d₂ is the second diagonal
Substitute the data,
Area of the tile = (45 × 30)/2
⇒ 1350/2
⇒ 675 cm²
Hence the area of each tile is 675 cm².
Therefore,
Area of 3000 tiles = 3000 × Area of 1 tile
⇒ 3000 × 675
⇒ 2025000 cm² = 202.5 m²
Now the total cost of polishing is given by,
Cost of polishing = Area of the tiles × Rate per m²
⇒ 202.5 × 4
⇒ 810 rupees
Hence the total cost of polishing the floor is 810 rupees.
hn appun hii kr rahi xD :P
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